Question

Consider an arithmetic sequence of algebraic form 3n+2. The what is the common difference of this sequence? What is the first term?​

Answer 1

QUESTION:

Consider an arithmetic sequence of algebraic form 3n+2. The what is the common difference of this sequence? What is the first term?

ANSWER:

Let,

$t(n) = 3n + 2$

so,

if we let n = 1

$t(1) = 3 \times 1 + 2 \\ t(1) = 5$

hence first term is 5.

now;

t = 2

$t(2) = 3 \times 2 + 2 \\ t(2) = 8$

second term is 8.

so,

$common \: differnce = t(2) - t(1)$

hence,

common difference = 8- 5

common difference= 3.

FINAL ANSWER :

$first \: term = 5 \\ common \: difference = 3$

plz Mark as brainliest

Answer 2

Answer:

first term =5

d=4

Step-by-step explanation:

xn=3n+2

put n=1, x1= 3×1+2

=3+2=5

then put n=2, x2 = 3×2+2

= 6+2=8

d=8-5=3☑️