.Consider an arithmetic sequence whose 7th term is 34 and 15th term is
66.
(a) Find the common difference,
(b) Find the 20th term.
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2 equations 2 variables
a+6d=34 and a+14d=66
Solve these equations
You will get d=4 and a=10
So common difference= 4
20th term => a + 19d = 10 + 19(4) = 86
a+6d=34 and a+14d=66
Solve these equations
You will get d=4 and a=10
So common difference= 4
20th term => a + 19d = 10 + 19(4) = 86
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