Question

Consider an array l[5,30] where each element l[i],5<=i<=30 is of 4 bytes and the address of L[5] is 1000. What is the address of L[12]

Answer 1

Answer:

1028

Explanation:

array I [5,6,7,8,9...............30]

one element 4 bytes

l[5] = 1000

l[12] = 1000 + 7*4bytes = 1028

* Here 7 indicates the numbers after 5 and upto 12 in array i.e 6,7,8,9,10,11,12

Answer 2

The Address of L[2] will be  988.

Explanation:

Given:-

   address of the array's 6th block (L[5]) = 1000

   Size of every element = 4 bytes

To find:-

   address of L[2}

Since, the address of L[5] is 1000

Address of L[2] will be 1000 - 4 - 4 - 4

                                 = 988