Question

Consider an atom of iron represented as 56 26Fe.
Give the number of I. protons II. electrons
III. neutrons present in the atom.

Answer 1

Answer:

Protons : 26

Electrons : 26

Neutrons : 30

Explanation:

In a representation of atom ᵃXₙ

n is the number of protons.

And it is equal to number of electrons if there is no charge on the atom.

Thus number of protons = Number of electrons in Fe = 26

Now 'a' is number of protons+neutrons

number of protons = 26

a = 56

number of neutrons = 56 - 26

                                 = 30

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