Consider an automobile moving at v mph that skids d feet after its breaks lock . calculate how for it would skid if it was moving at 2v and the breaks were locked
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Answer:
same retarding force so same acceleration
x = Vi t - (1/2) a t^2
v = Vi - a t
so for final v = 0
t = Vi/a
x = Vi^2/a - (1/2)Vi^2/a = Vi^2/a
if Vi new =2 Vi
then
x = 4 Vi^2/a
4 times as far
Explanation:
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