Physics, asked by anonymous26801, 3 days ago

Consider an automobile moving at v mph that skids d feet after its breaks lock . calculate how for it would skid if it was moving at 2v and the breaks were locked

Answers

Answered by gis5026
0

Answer:

same retarding force so same acceleration

x = Vi t - (1/2) a t^2

v = Vi - a t

so for final v = 0

t = Vi/a

x = Vi^2/a - (1/2)Vi^2/a = Vi^2/a

if Vi new =2 Vi

then

x = 4 Vi^2/a

4 times as far

Explanation:

Pls mark me the brainliest

Similar questions