Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength λ of that electron as(a) (0.259) nλ(b) √nλ(c) (13.6)λ
(d) nλ
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(d) is correct option
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Answer:
(d)n lambda
Explanation:
angular momentum=nh/2pi
mvr=nh/2pi
2.pi.r= nh/mv.
circumference=n.h/mv (circumference=2.pi.r)
=n.lambda (wavelength=h/mv)
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