Question

Consider an endothermic reaction $X \rightarrow Y$ with the activation energies, respectively, in general
(a) $E_b \ \textless \ E_f$
(b) $E_b \ \textgreater \ E_f$
(c) $E_b = E_f$
(d) There is no definite relation between $E_b$ and $E_f$

Answer 1

Ef is greater than Eb ∆H =Ef-Eb wher ∆H positive for endothermic then Ef is more than Eb