English, asked by abivelayutham1613, 11 months ago

Consider an EV with the following details. Total mass = 1200 kg, front area = 2 m 2 , aerodynamic drag
coefficient = 0.25 and tire rolling friction coefficient = 0.02, air density = 1.25 kg/m 3 , acceleration due to gravity =
10 m/s 2 . Equivalent mass for rotational mass can be taken as 6% of total mass. The wheel is connected to a
three phase induction motor with a gear. Gear efficiency is 0.9. Induction motor is operating in constant torque
region. The vehicle starts from rest and linearly reaches velocity of 80 km/hr in 10 seconds.
Aerodynamic drag at 10 sec is
 2000 N
 154.3 N
 25 N
 7 N
1 point
Rolling frictional force is
 240 N
 254.4 N
 278.4 N
 235.2 N
1 point
Tractive effort at 10 sec is
 3218.1 N
 3058.3 N
 10570.3 N
 3232.54 N
1 point
Power at the wheels is
 7144 W

 64.4 kW
 6429.6 W
 71.5 kW
1 point
Power at the motor shaft is
 71.56 kW
 6429.6 W
 79.5 kW
 7937.78 W
1 point
Percentage grade of the vehicle is
 26.2
 27.8
 26.36
 24.77
1 point
If gear ratio is increased by twice, the new tractive effort will be
 6436.3 N
 1609.07 N
 6116.6 N
 1529.15 N
1 point
Speed of the motor at 3 seconds is
 24 m/sec
 2400 m/sec
 666.6 m/sec
 6.7 m/sec
1 point
Tractive effort at 5 seconds is
 2942.5 N
 3218.13 N
 3102.3 N
 3058.3 N

Answers

Answered by Anonymous
0

Answer:

Bhai Corona aa gya aur tum kkkkkk OK sorry

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