Consider an example in which 18.0 grams of C6H12O6 is dissolved in 1 kg of water. What is the molality of the resulting solution?
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Answer:
△T=K
b
×
m
B
×w
A
w
B
×1000
△T=0.52×
180×1000
18×1000
T−T
0
=0.052
T−373=0.052
T=373.052K
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