Physics, asked by aryanbhatia5711, 9 months ago

Consider an excited hydrogen atom in state n moving with a velocity υ(ν<

Answers

Answered by dk6060805
2

Ratio of frequencies of the Emitted Radiation, \frac {\nu}{\nu_0} = (1+ \frac {u}{c})

Explanation:

  • Let the frequency emitted by the atom at rest be v_0
  • Let the velocity of hydrogen atom in state 'n' be u.

But u << c

  • Here, the velocity of the emitted photon must be u.
  • According to the Doppler's effect,
  • The frequency of the emitted radiation, ν is given by

Frequency of the emitted radiation,\nu = \nu_0 (1+ \frac {u}{c})/(1 - \frac {u}{c})

Since, u <<< c,

\nu = \nu_0  (1+ \frac {u}{c})/1

\nu = \nu_0  (1+ \frac {u}{c})

Ratio of frequencies of the emitted radiation, \frac {\nu}{\nu_0} = (1+ \frac {u}{c})

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