Question

Consider an ice cube of edge 1.0 cm kept in a gravity-free hall. Find the surface area of the water when the ice melts. Neglect the difference in densities of ice and water.

Answer 1

Answer :

Answer : A::B::C

Answer : A::B::CSolution :

Answer : A::B::CSolution : In the absence of gravilty the water which form due to melting of ice tens to acquire spereical surface.

Answer : A::B::CSolution : In the absence of gravilty the water which form due to melting of ice tens to acquire spereical surface. so, 6a3=(43)πr36a3=(43)πr3

Answer : A::B::CSolution : In the absence of gravilty the water which form due to melting of ice tens to acquire spereical surface. so, 6a3=(43)πr36a3=(43)πr3 →r=[18a34π]13→r=[18a34π]13

Answer : A::B::CSolution : In the absence of gravilty the water which form due to melting of ice tens to acquire spereical surface. so, 6a3=(43)πr36a3=(43)πr3 →r=[18a34π]13→r=[18a34π]13 So,surfacearea=4πr2

So,surfacearea=4πr2

So,surfacearea=4πr2 =4π[18a34π]23=4π[18a34π]23

So,surfacearea=4πr2 =4π[18a34π]23=4π[18a34π]23 =(36π)13cm2