Physics, asked by sangeethaseenivasan7, 6 hours ago

consider an inductor whose linear dimensions are tripled and the total number of turns per unit length is kept constant what happens to self inductance​

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Answered by Savagedrip07
0

Answer:

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Answered by Anonymous
2

Given: an inductor whose linear dimensions are tripled and the total number of turns per unit length is kept constant

To find: New self-inductance

Solution: Self-inductance is a property of conducting material that helps them to oppose the change of flow of current, a formula of which can be written as

L = μ0N^2A/l

here L is self-inductance, N is the total number of turns in the conducting coil, A is a cross sectional area, l is the length

we can write N that is the total number of turns as a product of number of turns × length

So, L = μ0( n×l)^2× l×l/l

L = L=μ0 ( n × l^3)

in this question n is constant and l is tripled

So Lnew = 27L

Therefore, self inductance will be increased by 27.

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