Question

Consider an object having mass 20kg moves with velocity 10m/s by applying a force 10N it comes to stop calculate the time taken by the object to stop by the applied force

Answer 1

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force = - 10N
mass of the object = 20kg
velocity (u)= 10m/s.
find (v)

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:
F = ma
-10 = 20 *a
a= -0.5m/s 2
using the first equation of motion , the time 't' taken by the body to come to rest can be calculated as,
v = u+at
therefore ,
t = -u/a
t = -10/-0.5
t = 20 seconds.
therefore time taken by the object to stop is 20 seconds.

Answer 2

Answer:

800 joule

Explanation:

As there is no external non-conservative force on the system (both masses altogether) the linear momentum should

be conserved.

Thus we should have m

1

v

1

+m

2

v

2

=(m

1

+m

2

)V (inelastic collision)

V is the common velocity after the collision.

putting values we get 20(10)+5(0)=(20+5)V or V=8m/s

so the new KE will be K=

2

1

mV

2

=0.5×25×64=800Joule

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