Question

Consider an object of mass 2 kg resting on the

floor. The coefficient of static friction between the

object and the floor is s = 0.8. What force must be

applied to the object to move it?​

Answer 1

Answer:

16 N

Explanation:

(fs)max=μR

           =μ(mg)

           =0.8×2×10

           =16 N