Question

Consider an unfair coin. The probability of getting heads is 0.6. If you toss this coin twice,
what is the probability that the first or the second toss is heads?
(A) 0.56 (B) 0.64 (C) 0.84 (D) 0.96

Answer 1

Answer:

Option(C)

Step-by-step explanation:

Given that Probability of getting heads is 0.6.

Then,Probability of getting tails = 1 - 0.6 = 0.4.

Now,

Total number of coins tossed = 2.

Possible outcomes = {HH,TH,HT,TT}.

Probability that first or second toss is heads:

= {HH, TH, HT}

∴ Required probability = 0.6 * 0.6 + 0.4 * 0.6 + 0.6 * 0.4

                                     = 0.84.

Hope it helps!