Question

Consider an unfair. The probability of getting ahead is. 6 if you toss this coin twice what is the probability that the first or the second toss is heads

Answer 1

So the total possibilities for two tosses is {HH,TT,HT,TH} out of which we want {HH,HT,TH}

So probability is 0.6*0.6 + 0.6*0.4 + 0.4*0.6 = 0.84 (option C)