Consider any two triangles ABC and MNO, 3 Marks
where AB=5cm, BC=7cm, AC=6cm and MN=5cm,
NO=7cm and MO=6cm. Find the condition of congruence.
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Answer:
Correct option is
A
∠B>∠A>∠C
In any triangle angle opposite to the longer side is larger.
Here CA is the longest side and angle opposite to it is ∠B.
So ∠B is largest angle.
Then comes BC and angle opposite to it is ∠A
So angle A is second largest.
Then comes AB angle opposite to it is ∠C
So ∠C is smallest.
So the decreasing order of angles is
∠B>∠A>∠C
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