Question

Consider arithemethic sequence 12, 23, 34 Write the algebric expression ( n' th term)

Answer 1

Answer:

Given arithmetic sequence is 9, 15, 21,.

First term = a = 9

Common difference = d =15 9 = 6

(A) For natural number n

nth term = [(n−1)x6]+9=6n+3 where n=1,2,3,

Hence algebraic form of the sequence 9,15,21,. is x

n

=6n+3.

Answer 2

Explanation:

nth term can be expressed as

$tn \: = 12 + (n - 1) \times 11$

where first term = 12

common difference = 11