Question

Consider arithmetic sequence 10, 14, 18,
(a) What is the common difference?
(6) Find the 21st term?
(c) find the algebraic form of this sequence ?
(d) which term of this sequence is 66?​

Answer 1

Step-by-step explanation:

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Answer 2

SOLUTION

TO DETERMINE

Consider arithmetic sequence 10, 14, 18,

(a) What is the common difference?

(b) Find the 21st term?

(c) find the algebraic form of this sequence ?

(d) which term of this sequence is 66?

EVALUATION

Here the given arithmetic sequence is 10, 14, 18,

First term = a = 10

Common Difference = d = 14 - 10 = 4

(a) Common Difference = 4

(b) 21 st term

= a + ( 21 - 1 ) d

= a + 20d

= 10 + ( 20 × 4 )

= 10 + 80

= 90

(c) Here the n th term of the sequence is

= a + ( n - 1 ) d

= 10 + ( n - 1) × 4

= 10 + 4n - 4

= 4n + 6

Hence the algebraic form of this sequence = 4n + 6

(d) Let n th term is 66

So by the given condition

4n + 6 = 66

$\implies \sf{4n = 60}$

$\implies \sf{n = 15}$

So 15 th term of this sequence is 66

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