Question

consider arithmetic sequence 5,8,11
a) what is its common difference
b) what was its 11th term
c)what is the remainder when each term of this sequence is divided by the common difference​

Answer 1

Answer:

a) d = 3

Step-by-step explanation:

The nth term of series is given by :

a + (n-1)d

a is the first term, d is common difference, n is nth term

a = 3

looking at the second element, we have:

5 + (2 - 1)d = 8

5 + d = 8

d = 3

b) given series is 5, 8, 11

here, a = 5, d = 3, a11 = ?

a11 = 5 + (11-1)3

a11 = 5 + 30

a11 = 35

thus, the 11th term is 35

Answer 2

Step-by-step explanation:

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