Question

consider Arthematic sequence
6, 10, 14......... find 20th term and 40th term of this sequence ​

Answer 1

refer the following attachment for step by step explanation

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Answer 2

Answer:

20th term - 82 and 40th term - 162

Step-by-step explanation:

In the following arithmetic progression, the first term i.e. a = 6

the common difference i.e. d=4

Now going by the formulae we will get the 20th term= {6+(20-1)4}

=(6+76) = 82

And the 40th term={6+(40-1)4}

={6+156) = 162.