Consider f:R_R given by f(x)=5x-3.show that f is invertible and find the inverse
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Answer :
Inverse function : g(x) = (x + 3)/5
Note :
★ A function f(x) is said to be invertible if it is one-one onto function .
★ One-One function : A function f(x) is said to be one-one if
f(x1) = f(x2) => x1 = x2 .
★ Onto function : A function f(x) is said to be onto function if Range = Co-domain .
Solution :
Given function :
f : R → R , f(x) = 5x - 3:
★ Whether f(x) is one-one :-
Let f(x1) = f(x2)
=> 5x1 - 3 = 5x2 - 3
=> 5x1 = 5x2
=> x1 = x2
Since , f(x1) = f(x2) => x1 = x2 , thus the given function f(x) is one-one .
★ Whether f(x) is onto :-
Let y = f(x)
=> y = 5x - 3
=> 5x = y + 3
=> x = (y + 3)/5
For x to be real , y can be any real number .
=> Range = R
=> Range = Co-domain
Since , Range (f) = Co-domain (f) , thus the given function f(x) is onto .
Clearly ,
The function f(x) is one-one onto , thus it is invertible .
Also ,
The inverse of the given function f(x) will be given as ;
g(x) = (x + 3)/5
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