Computer Science, asked by nagamanidasari3, 7 months ago

Consider FORTY+TEN+TEN=SIXTY where each letter represents a unique
value from 0 to 9, Find (S+I+X+T+Y).
A)
20
B)
21
C)
22
D)
23
E)
24

Answers

Answered by ananya12534

Answer:

If AA + BB = ABC, then what is the value of A+B+C= ?

Ans: Option 2

Explanation:

A A

B B +

C C

-----------

A B C

------------

The digits are distinct and positive. Let’s first focus on the value A, when we add three 2 digit numbers the most you get is in the 200’s (ex: AA + BB + CC = ABC à 99 + 88 + 77 = 264). From this, we can tell that the largest value of A can be 2. So Either A = 1 or A = 2.

Now focus on value B, let’s take the unit digit of the given question: A + B +C = C (units). This can happen only if A + B = 0 (in the units) à A and B add up to 10.

, correspondingly we have N + U = 10 or 9 or 8. But duplication is not allowed, so N = 8 with "carry 2" from ONOT. Hence, O + O = T + 20 - 8 = T + 12. Testing for T = 2, 4 or 6, we find only T = 2 acceptable, O = 7. So we have 87 + 908 + 87 = 1082.

Answer is 1082

4. MAC + MAAR = JOCKO, find the value of 3A + 2M + 2C.

Ans: Option 1

Explanation:

M A C

+ M A A R

------------------

J O C K O

------------------

Here J is carry, J=1 when J=1, O=0 with carry 1 and M=9 C+R=O à 0 with carry 1. So, C=2 and R=8 M+A=C à 2 with carry 1, A=3, A+A+1= K, 3+3+1=K=7, 932+9338=10270 so, finally A = 3, M = 9, C = 2, = 3A + 2M + 2C = 9 + 18 + 4 = 31

Answer is 31

5. SEND + MORE = MONEY, find the value of M+O+N+E+Y.

Ans: Option 2

Explanation:

S E N D

+ M O R E

-----------------

M O N E Y

-----------------

From the given data, the value of M will be 1 because it is the only carry-over possible from the sum of 2 single digit numbers in column 4. M = 1, S + 1 = a (two digit number). So S = 1 and O cannot be 1 but 0. Also E and N are consecutive. With trial and error possibilities, we get SEND = 9567, MORE = 1085 and MONEY = 10652.

So, M + O + N + E + Y = 1 + 0 + 6 + 5 + 2 = 14

Answer is 14

6. If “EAT + THAT = APPLE”, what is the sum of A+P+P+L+E?

Ans: Option 3

Explanation:

E A T

+ T H A T

------------------

A P P L E

------------------

From the given data, the value of A will be 1 because it is the only carry-over possible from sthe um of 2 single digit number. T maximum it can take only 9 and there should a carryover for T to give sum as 2 digit number. So T =9, P = 0, A = 1. T + T = 18, the value of E is 8 and 1 will be a carry over to the next column. That is 1 + A + A= L = 3. And finally H = 2. Hence, 819 + 9219 = 10038. A+P+P+L=E = 1+0+0+3+8 = 12.

Answer is 12

7. If POINT + ZERO = ENERGY, then E + N + E + R + G + Y = ?

Ans: Option 1

Explanation:

P O I N T

+ Z E R O

-----------------------------

E N E R G Y

-----------------------------

From the given data, the value of E will be 1 because it is the only carry-over possible from sum of 2 single digit number. E = 1, P = 9, N = 0, and N + R = G, 0 + R = G but R = G not possible. 1 + R = G possible. So R and G are consecutive. G > R. 1 + I = R, so I and R are consecutive. R > I. i.e., G > R > I. and G, R, I are consecutive. Now O + T should give carry over and O + Z also give carry over. So O is bigger number. Now take values for G, R, I as 8, 7, 6 or 7, 6, 5 etc. and do trial and error. POINT = 98504, ZERO = 3168 and ENERGY = 101672. So E + N + E + R + G + Y = 1 + 0 + 1 + 6 + 7 +2 = 17

Answer is 17

8. YOUR + YOU = HEART (Assume O = 4). Find the value of Y + U +R +E.

Ans: option 3

Explanation:

Y O U R

+ Y O U

------------------

H E A R T

-------------------

Given the value of O as 4, Y and E cannot be the same, so there should be a carry-over 1. 1 + Y = 10, so E will take 0 and H as 1. O + Y = A (4 + 9 = 13) i.e. A = 3. Now, U + O (4) =R (which can only be a single digit number), U cannot take 5, 3, 4 and only possibility will be 2. If U is 2, then R will be 6. R + U = T, 6 + 2 = 8(T = 8). Hence, the value of Y + U + R + E = 9 + 2 + 6+ 0 = 17.

Answer is 17

9. TOM + NAG = GOAT, find the value of G+O+A+T.

Cannot be determined

Ans: Option 4

Explanation:

T O M

+ N A G

-------------------------

G O A T

------------------------

Adding two single digit number the maximum carry it can have is 1, so G=1.

O + A = A, from this we can tell that O = 0. T + N = O (O should be a two digit number ending in zero, only then G will be 1). Sum of T and N should be 10 i.e. T (6) + N (4) = 10. M + G = T, from this we will get the value of M as 1.

O=0, G=1, N=4, M=5, T=6 and the left out numbers are 2, 3, 7, 8, 9, from this A can take any value. There is no definite value for A.

Answer is: Cannot be determined

10. FORTY + TEN + TEN = SIXTY, find the value of T+E+N.

Ans: Option 2

Answered by jhangir789

Conclusion

Substitution Cipher

A substitution Cipher is a way of encrypting that uses a key to replace units of plaintext with ciphertext in a predetermined manner; the "units" can be single letters (the most common), pairs of letters, triplets of letters, mixes of the aforementioned, and so on. To retrieve the original message, the receiver deciphers the text via the inverse substitution technique.

Substitution cyphers are similar to transposition cyphers. The plaintext units are rearranged in a different and frequently fairly complex sequence in a transposition cypher, but the units themselves remain unaffected. With contrast, in a substitution cypher, the plaintext units are kept in the same order in the ciphertext, but the units themselves are changed.

Main Content

1-easy to see: F 9 R T Y

N=0, E=5, O=9, I=1 T 5 0

+ T 5 0

--------------

S 1 X T Y

2-also apparent: 2 9 7 8 6

S=F+1,so S/F=2/3/4, 8 5 0

since R+T+T>19; 8 5 0

---------------

so, with minimun trial&error: 3 1 4 8 6

to, learn more about Substitution Cipher