Question

consider number 7^n ,where n is natural number check whether there is any value for which 7^n ends with the digit 0

Answer 1

Any positive integer ending with the digit zero is divisible by 5, and so it's prime factorisation must contains the prime of 5

We have,
7^n = 7into 1
1. The only prime in the factorisation of 7^n is only 7 and 1
2. There is no other prime in the factorisation of 7^n
3. By the uniqueness of the FUNDAMENTAL THER OF ARITHMETIC,
4. 7^n does not end with the digit zero.

Answer 2

❤ hOlA mAtE ❤

==> Any positive integer ending with the digit zero is divisible by 5 , and so it's prime factorisation must contains the prime of 5.

==> We have , 7 ^ n = 7into 1 1.

==> The only prime in the factorisation of 7 ^ n is only 7 and 1 2.

==> There is no other prime in the factorisation of 7 ^ n 3.

==> By the uniqueness of the FUNDAMENTAL THER OF ARITHMETIC , 4.

==> 7 ^ n does not end with the digit zero .

Hope it helps you ✔️