Consider obtuse-angled triangles 9cm,21cm and x cm. if 21 is the greatest side and x is an integer, then how such triangles exist a)5 b)6 c)7 d).8
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if 21 is the largest side then
21^2 >9^2+x^2
441-81>x^2
360>x^2
so x^2 can not be greater than 360 so x =18
21-9<x<21+9
so values of x are 13 ,14,15,16,17,18
so our ans is 6
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