Question

Consider points A(4, 3) and B(x, 5) on the circle with centre O(2, 3). Then the value of x is: ?

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Answer 1

Step-by-step explanation:

OA=OB

√(4-2)^2+(3-3)^2=√(x-2)^2+(5-3)^2

√(2^2)+(0)^2=√(x-2)^2+(2)^2

√4+0=√(x-2)^2+4

√4=√(x-2)^2+4

2=√(x-2)^2+4

√(x-2)^2+4=4

√(x-2)^2=0

x-2=0

X=2