Consider right triangle ABC, right angled at B. If AC = 17 units and BC = 8 units determine all the trigonometric ratios of angle C.
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Answer:
AB^2=AC^2-BC^2
=289-64
AB^2=225
AB=15
sinc=AB/AC=15/17
cosc=BC/AC=8/17
tanc=AB/BC=15/8
cosec c=17/15
sec c=17/8
cot c=8/15
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