Question

Consider right triangle ABC, right angled at B. If AC=17units and BC=8units
determine all the
trignometric ratios of angle C.​

Answer 1

Step-by-step explanation:

let us calculate the length of AB

In Δ ABC, using Pythagoras theorem,

AC2=AB2+BC2⇒AB=AC2−BC2−−−−−−−−−−√=172−82−−−−−−−√=289−64−−−−−−−√=225−−−√=15

AB = 15 units .

Now let us calculate the trigonometric ratios of angle C

sin C = opposite side/hypotenuse=AB/AC= 15/17

cos C = adjcent side/hypotenuse=BC/AC= 8/17

tan C =opposite side/adjcent side =AB/BC= 15/8

cot C =1/tan C =adjcent side/opposite side = BC/AB = 8/15

sec C = 1/cos C = hypotenuse/adjcent side = AC/BC= 17/8

cosec C = 1/sin C = hypotenus/eopposite side =AC/AB= 17/15