Chemistry, asked by ishitashitlani, 10 days ago

Consider that 5g of sugar is dissolved in beaker A, 30g of sugar in beaker B, 70g in beaker C and 100g in beaker D. What is the correct order of boiling point of the mixtures?

A. Beaker D > Beaker A > Beaker B > Beaker C

B. Beaker D > Beaker C > Beaker B > Beaker A

C. Beaker A > Beaker B > Beaker C > Beaker D

D. Beaker A > Beaker C > Beaker B > Beaker D​

Answers

Answered by pranjalboro582
0

Answer:

B. Beaker d greater than beaker c greater than beaker b greater than beaker a

Answered by rameshrajput16h
0

Answer:

(i) Colloidal solution scatters light. Beaker B, which has a colloidal solution, will do so.

(ii) Beaker B, having a colloidal solution, will have Brownian movement.

(iii) Sugar dissolves completely in water. Hence Beaker A has a true solution. Beaker B has a colloidal solution of starch in water.

(iv) Since sugar in water is a true solution, it is also a homogeneous solution.

(v) A true solution has particles of size 10

A

o

to 2000

A

o

. Hence Beaker A will have such particles.

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