Question

Consider the A.P – 6,9,12,15,18……………………Find the 13th and 15th term of the

following.​

Answer 1

Answer:

42 and then 48

13 multiply by 3= 39 + 3= 42

15 multiply by 3 = 45 + 3 = 48

Answer 2

Given-

A.P – 6,9,12,15,18……………………

To find-

13th and 15th term

Solution-

$a = 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ d = 9 - 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\\ = 3\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ an = a + (n - 1)d \\ \\ a13 = 6 + (13 - 1)3 \\ = 6 + 12(3) \\ = 6 + 36 \: \: \: \: \: \\ = 42 \: \: \: \: \: \: \: \: \: \: \: \: \\ \\a15 = 6 + ( 15 - 1)3\\ = 6 + 14(3) \\ = 6 + 42 \: \: \: \: \: \\ = 48 \: \: \: \: \: \: \: \: \: \: \: \:$