Question

consider the Arithametic Sequence 135,141,147,.... can the sum of any 25consecutive terms of the sequence be 2016?​

Answer 1

Answer:

Flase

Step-by-step explanation:

Sum of Arthematic sequence is

[n/2(2a+n-1) d]

n=no.of terms=25

a=first term =135

d=distance=6

25/2 (2×135+(25-1) 6)

25/2 (170+(24) 6)

25/2 (170+144)

25/2(314)

25(157)

=3925

No the sum of 25 Consecutive terms is 3925

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