Question

Consider the arithemetic sequence
135, 141, 147 etc.
Can the sum of any 25
Consicutive terms of the
Sequence is 2016. Justify your answer.​

Answer 1

Step-by-step explanation:

No of terms=25

Common difference=6

According to question;

        2016=25/2 × [2a+24(6)]                           [S=n/2[2a+(n-1)d]]

        2016=25/2 × (2a+144)

        2016=25(a+72)

          a+72=80.64

          a=8.64

Since we dont get an integer as we should had in this AP, the statement is false.