Consider the arithmetic sequence 10, 16, 22.Can you find out any terms as the sums or difference of any 2 terms of the sequence
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Answer:
5th term
a + 4d = 22
a= 22 - 4d
15th term
a+ 14d = 62
22-4d +14d = 62
d= 40/10
d= 4
using first equation...
a+4d = 22
a+ 16 = 22
a= 6
100th term
a+ 99d =?
6 + 396
= 402
sum of first 50 terms
x =(n/2)[2a +({n-1}d]
= (25)( 12 +(49 X 4))
5200 (calculate)
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