Question

Consider the arithmetic sequence 10, 16, 22.Can you find out any terms as the sums or difference of any 2 terms of the sequence​

Answer 1

Answer:

5th term

a + 4d = 22

a= 22 - 4d

15th term

a+ 14d = 62

22-4d +14d = 62

d= 40/10

d= 4

using first equation...

a+4d = 22

a+ 16 = 22

a= 6

100th term

a+ 99d =?

6 + 396

= 402

sum of first 50 terms

x =(n/2)[2a +({n-1}d]

= (25)( 12 +(49 X 4))

5200    (calculate)