consider the arithmetic Sequence 3 8 13 write it's algebraic form
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3, 8, 13, 18, 23, 28, 33, 38, ...
This sequence has a difference of 5 between each number.
arithmetic sequence 3,8,13,18
The values of a and d are:
a = 3 (the first term)
d = 5 (the "common difference")
Using the Arithmetic Sequence rule:
xn = a + d(n−1)
= 3 + 5(n−1)
= 3 + 5n − 5
= 5n − 2
So the 9th term is:
x9 = 5×9 − 2
= 43
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