consider the arithmetic sequence 4,9,14
a) find 11th term
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1
Answer:
11th term=a+(11-1)d=4+10(5)
=54
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Answered by
1
Answer:
54
Step-by-step explanation:
Here ,
First term of A.P. , a= 4.
The common difference = difference between successive terms in AP = 14-9 =9-4 = 5
The nth term in A.P. sequence is given by,
- a(n) = a + ( n-1 )d
- The 11th term, a(11) = a +(11-1)d
- a(11) = 4 + 10*5 = 4 + 50 = 54
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