Question

consider the arithmetic sequence 41,38,35,32 find the position of first negative term of this sequence​

Answer 1

Hey mate !! here's your answer ✌️

Answer :-

We can solve it with hit and trial method .

Let us consider the negative number to be -1

So by using the formula = a+(n-1)d where a=41 , d= -3

=> 41+(n-1)-3 = -1

=>41 -3n +3 = -1

=>44-3n = -1

=>-3n = -44-1

=>n= -45/-3

Therefore n= 15 , so we can say that the first negative tern of the given ap is the fifteenth term which is -1 .

We can verify this by replacing the value of n in the formula a+(n-1)d .

Hope it helps ya cheerio....

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