Question

Consider the Arithmetic sequence 6 10 14...
a)what is its comman difference?

Answer 1

$Given \: Arithmetic \: sequence : 6,10,14\ldots$

$First \:term ( a = a_{1} ) = 6$

$a_{2} = 10$

$Common \: difference (d) = a_{2} - a_{1}$

$= 10 - 6$

$= 4$

Therefore.,

$\red{ Required \: Common \: difference }\green { = 4 }$

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Answer 2

$\huge \: answer : \\ \\ given \: \: ap \: \: 6 \: ,\: 10 \: , \: 4 \: \\ \\ a = 6 \\ \\ common \: \: difference \: \: = a_2 - a_1 = 10 - 6 = 4 \\ \\ \therefore \red {\: common \: \: difference(d) = 4}$

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