Question

Consider the arithmetic sequence 6, 10,14

a) What is its 20th term ?

b) Find the position of the term obtained by adding 100 to the 20 th term?

c) What is its 45 th term?

d) Find the position of the term obtained by subtracting 96 from its 45th term ?​

Answer 1

Answer:

a1=6, d=4

a20=6+(20-1)×4=6+76=82

100+82=182

182=6+(n-1)×4=6+4n-4=2+4n

4n=182-2=180

n=45

45th term is 182

182-96=86

86=6+(n-1)×4=6+4n-4=2+4n

4n=86-2=84

n=21