Question

consider the arithmetic sequence7, 11,15,19
Can the sum of any 20 terms of this sequence is 2017
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Answer 1

Answer:

$\blue{\mathfrak{\underline{\large{arithmetic \: sequence}}}:} \\ let \: take \: first \: 20 \: terms\\ 7,11,15,19,……,83 \\ a=7, \: d=4, \: l=83, \: S_{20}=2017\\ S_{n} = \frac{n}{2}(a + l)\\ S_{20} = \frac{20}{2} (7 + 83) \\ 2017 = 10 \times 90 \\ 2017=900 \\ L.H.S≠R.H.S \\ hence, \: the \: sum \: of \: any \: 20 \: terms \\ \: of \: this \: sequence \: is \: not \: equal \: \\ to \: 2017. \\ \\\red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$