Consider the arthemetic sequnce 11,15,19....327
A.write the algebric form of this sequence
B.How many terms are there in the sequnce
C.Calculate the sum of the terms
D. Can the sum of any 25 terms of this sequnce 2020 Why
Answers
Answered by
0
Answer:
a, a+d, a+2d, a+3d......
let there be n terms. then
327 = 11 + (n-1)×4
(n-1)×4=327-11=316
n-1=316/4=79
n=79+1=80
sum = (n/2)×(1st term + last term)
=(80/2)×(11 + 327) = 13520
Similar questions