Question

Consider the bandwidth as 50 Kbps, one way transit time-240 msec and the segment size is 1000 bit. Consider the event of a segment transmission and the corresponding ACK reception. Find the maximum number of segments that can be outstanding during this duration.

Answer 1

There are 23 segments that can be outstanding during this duration.

Explanation:

• Bandwidth is defined as the number of frequencies in a specific signal.

• Segment transmission is used by networks related to communication.

• This is a data package. It is segregated into small units. These units are used for transmission.

• ACK is abbreviated as acknowledgment code. These are a set of signals that any computer sends for transmission of data.

Answer 2

Answer:

25

Explanation:

Maximum number of outstanding segments = 2*BDP +1

BDP in bandwidth delay product = 50*.24 = 12Kbit

since we have 1000 bit segment 12 data segments will be outstanding and

12 ACK will be outstanding and +1 for one ACK which has just reached the sender.