Question

consider the body moving with a velocity 2 m/s. it is
accelerated by -2m/s2. find distance after 5 sec​

Answer 1

Given :-

• Initial velocity (u) = 2 m/s
• Acceleration (a) = - 2 m/s²
• Time (t) = 5 seconds

To find :-

• Distance (s)

According to the question,

By using Newtons second equation of motion,

→ s = ut+ ½ at²

Where,

• s stands for Distance
• a stands for Acceleration
• u stand for Initial velocity
• t stands for Time

→ Substituting the values,

→ s = 2 × 5 + ½ × (-2) × 5 × 5

→ s = 10 + (-25)

→ s = 10 - 25

→ s = -15

As we know that distance can't be negative so we will take it as positive.

.°. The distance is 15 m.

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Answer 2

Given:-

• Initial Velocity (u) =2m/s
• Acceleration (a) = 2m/s
• Time (t) =5 seconds

To find:-

• Distance

According To the question,

By using Newton's Second Equation Of motion,

➡ s = ut + 1/2at

Where,

• s stands for Distance
• a stands for acceleration
• u stands for initial velocity
• t stands for time

substituting the value

➡s = 2× 5+1/2 +(-2)×5×5

➡s = 10+(-25)

➡s = 10-25

➡s= -15

As we know that distance can't be negative so we will take it positive.

The Distance is 15 m.

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