Consider the case of freely falling body given in
the figure:
At A,
Kinetic energy=0 and
Potential energy=mgh
At B,
Kinetic energy=mgx
At C,
Kinetic energy=mgh and Potential energy=0
a) Find the potential energy of the body at B.
b) Find the total energy at A,B and C.
c) Is there any variation in total energy?
What do you infer from the result?
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Answer:
(a) Since total mechanical energy is conserved at each point in path,
KE
B
+PE
B
=KE
A
+PE
A
mgx+PE
B
=0+mgh
PE
B
=mg(h−x)
(b)Total energy at A=KE
A
+PE
A
=mgh
Total energy at B=KE
B
+PE
B
=mgh
Total energy at C=KE
C
+PE
C
=mgh
(c) There is no variation in total energy.This shows that the total energy is always conserved.
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Explanation:
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