Question

Consider the charges q,q and -q placed at the vertices of an equilateral triangle what is the force on each charge. with proper explanation plzz.

Answer 1

Answer:

F ( at A ) = 1 / 4πε₀ q² / x²

F( at B ) = 1 / 4π ε₀ q² / x²

F ( at C ) = √ 3 1 / 4π ε₀ q² / x²

Explanation:

1) Plzz see the attachement

2) We know that , charges of same sign applied repulsive force on each other , and charges of opposite sign applied attractive force on each other.

3) We know that , electrostatic force between two charges q₁ and q₂ and at a distance r between them is ,

F = ( 1 / 4πε₀ ) ( q₁ q₂ / r² )

4) We know that ||gm law of vectors

R² = P² + Q² + 2PQ Cosθ

5) We know that, resultant of equal vectors bisect the angle between them .