Consider the circuit given below. Calculate the current in various resistances.
2002
F
A
592
w
B
40 V1
90 V
602
Answers
Answered by
0
When 8 and 12 are in parallel
and 7.2 is in series with them
Net Resistance
10
7.2
+
12+8
8×12
=
10
72
+
20
96
=
10
72
+
10
48
=
10
120
=12Ω
Total current =
netR
V
=
12
6
=0.5Ω
Voltage across R
1
=iR
1
=0.5×7.2
=3.6
solution
and 7.2 is in series with them
Net Resistance
10
7.2
+
12+8
8×12
=
10
72
+
20
96
=
10
72
+
10
48
=
10
120
=12Ω
Total current =
netR
V
=
12
6
=0.5Ω
Voltage across R
1
=iR
1
=0.5×7.2
=3.6
solution
Similar questions