Question

Consider the circuit in the figure.The potential at point O is?​

Answer 1

Hi mate

Yr answer is 13/2 volt .

Answer 2

The answer is $\bf V=\frac{64}{11} V$.

Given:

Three batteries of 10 V, 4 V and 5 V

Three Capacitors of 2 μF, 1 μF, and 3 μF

To Find:

The potential at point O

Solution:
Let the potential at point O be V.

Let the charge on 2 μF be $Q_1$

Let the charge on 1 μF be $Q_2$

Let the charge on 3 μF be $Q_3$

Therefore using conservation of charge, we know

$Q_1 =Q_2 +Q_3$

Using the voltage rule, we get

$Q_1 = \frac{10-V}{2}\\\\Q_2 =\frac{V-4}{1} \\\\Q_3=\frac{V-5}{3}$

Therefore

$\frac{10-V}{2}=\frac{V-4}{1}+\frac{V-5}{3}\\\\30-3V=6V-24+2V-10\\\\11V=64\\\\V=\frac{64}{11} V$

Hence the potential at point O is $\bf V=\frac{64}{11} V$.

#SPJ2