Question

Consider the circuit shown in fig. Calculate the
current through the 3 ohm resistor.​

Answer 1

Answer:

4/3ampere should be the current in 3 ohm resistor

Answer 2

Solution

let 6ohm be R1 be 3ohm and R2 be 6ohm and R3 be 4ohm

clearly we can see 6ohm and 3ohm resistor is connected in parallel

so

$resistance = \: \frac{r1r2}{r1 + r2}$

so by putting value

$resistance \: = \frac{3 \times 6}{3 + 6} \\ \\ resistance = \frac{3 \times 6}{9} \\ resistance \: = \frac{18}{9} \\ \\ resistance = 2ohm \:$

Now we can see that R1,2 and R3 are connected in series

so

$resistance \: = r1.2 + r3 \\ \\ resistance = 2 + 4 \: \: resistance \: = 6ohm$

Now

Voltage = 12v

so current

$i = \frac{v}{r} \\ \\ i = \frac{12}{6} \: \: i = 2ampere$

total voltage at 4ohm resistor

V1 = IR

V1 = 2(4)

V1 = 8 v

Now voltage at 3 ohm and 6 ohm resistor

V - V1 = 12 - 8 = 4v

so current at 3ohm

$i = \frac{v2}{r3} \\ \\ i = \frac{4}{3}$

then current is = 1.3 ampere

hope it helps

be brainly