consider the circuit shown in the figure at the steady state the current supplied by the battery and the charge on the capacitor are respectively :
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Answer:
At steady state, current through capacitor is zero, because capacitor get fully charged.
Current through resistor 4Ω gets zero.
Total resistance
R
total
1
=
R
1
1
+
R
2
1
+
R
3
1
=
1
1
+
2
1
+
3
1
=
6
11
R
total
=
11
6
Ω
I=
R
total
V
=
11
6
6
=11A
Fully charge capacitor Q=CV=0.5×10
−6
×6=3μC
Current is 11A and charge 3μC
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