Question

Consider the circuit shown in the figure. The voltmeter on the left reads 10V and that on the right reads 8V. Find a) the current through the resistance R, b) the value of R and c) the potential difference across the battery.

Answer 1

Answer:

(a) Since R and 6 resistors are in series, same current flows through them, i.e.,

    Current 'I' through the resistor can be written as (6V / R)

    I = V / R

      6v/R=12v/6Ω

R=3Ω

(ii) Ammeter reading will be same as current through R, i.e.

      6V/3Ω=2A

     

(iii) Potential difference across the battery terminals is 6v+12v=18V