Question

Consider the client A sends the data of 12 bytes to the sender B using the UDP. what is the efficiency of the transmission at the UDP level assuming no options in the UDP header.

a)12/40
b)28/40
c)12020
d)28/36​

Answer 1

The transmission ratio is 12 / 20

Explanation:

We are given that:

• The data sent by A to the client = 12 bytes
• The sender = B
• To Find: Efficiency of transmission

Solution:

As we know that

The length of UDP header = 8 bytes

The formula is

Transmission ratio = Data / Data + UDP

Transmission ratio = 12 / 12 + 8

Transmission ratio = 12 / 20

Thus the transmission ratio at UDP level is 12 / 20